DCC-2036 (Rebastinib)

目录号: A11200

Bcr-Abl 抑制剂

DCC-2036 (Rebastinib)

DCC-2036 (Rebastinib) Chemical Structure

CAS NO. 1020172-07-9

DCC-2036 (Rebastinib)是一种Bcr-Abl抑制剂,作用于Abl1(WT)和Abl1(T315I),IC50分别为0.8 nM和4 nM,也抑制SRC, LYN, FGR, HCK, KDR, FLT3,和Tie-2,对c-Kit具有低的抑制活性。

库存: 现货

规格 价格 数量
5 mg
¥ 455.00
10 mg
¥ 770.00
50 mg
¥ 1,820.00
100 mg
¥ 2,800.00
10mM * 1mL in DMSO
¥ 840.00
Warning 产品仅用于科学研究,不针对患者销售,望谅解.

产品详情

DCC-2036 (Rebastinib)是一种Bcr-Abl抑制剂,作用于Abl1(WT)和Abl1(T315I),IC50分别为0.8 nM和4 nM,也抑制SRC, LYN, FGR, HCK, KDR, FLT3,和Tie-2,对c-Kit具有低的抑制活性。
Targets
Target Value
u-Abl1(native)IC50: 0.75nM
Abl1(H396P)IC50: 1.4nM
p-Abl1(native)IC50: 2nM
FLT3IC50: 2nM
p-Abl1(T315I)IC50: 4nM
KDRIC50: 4nM
u-Abl1(T315I)IC50: 5nM
Tie-2IC50: 6nM
LynIC50: 29nM
SrcIC50: 34nM
FGRIC50: 38nM
HckIC50: 40nM
PDGFRαIC50: 70nM
PDGFRβIC50: 113nM
c-KitIC50: 481nM
AuroraAIC50: >5μM
CDK2/CyclinDIC50: >5μM
In vitro (25°C) DMSO 103 mg/mL (186.05 mM)
Water Insoluble
Ethanol 15 mg/mL (27.09 mM)
In vivo 0.5% CMC+0.25% Tween 80 15 mg/mL
* <1 mg/ml means slightly soluble or insoluble.
* Please note that Adooq tests the solubility of all compounds in-house, and the actual solubility may differ slightly from published values. This is normal and is due to slight batch-to-batch variations.
Concentration / Solvent Volume / Mass 1 mg 5 mg 10 mg
0.1 mM 18.06 mL 90.32 mL 180.64 mL
0.5 mM 3.61 mL 18.06 mL 36.13 mL
1 mM 1.81 mL 9.03 mL 18.06 mL
5 mM 0.36 mL 1.81 mL 3.61 mL

*The above data is based on the productmolecular weight 553.59. Batch specific molecular weights may vary from batch to batch due to solvent of hydration, which will affect the solvent volumes required to prepare stock solutions.

目录号 A11200
作用机制 Inhibitor (抑制剂)
M. Wt 553.59
Formula C30H28FN7O3
Purity >99%
Storage

Store lyophilized at -20ºC, keep desiccated.
In lyophilized form, the chemical is stable for 36 months.
In solution, store at -20ºC and use within 3 months to prevent loss of potency. Aliquot to avoid multiple freeze/thaw cycles.

CAS No. 1020172-07-9
Synonyms DCC2036
SMILES CC(C)(C)C1=NN(C(=C1)NC(=O)NC2=C(C=C(C=C2)OC3=CC(=NC=C3)C(=O)NC)F)C4=CC5=C(C=C4)N=CC=C5

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