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T0070907

目录号: A11588
PPAR-γ 拮抗剂
T0070907 被确认为一种强效且选择性的 PPARgamma 拮抗剂。其表观结合亲和力(50%抑制[(3)H]罗格列酮结合的浓度或 IC(50))为1纳摩尔,T0070907 在人类 PPARgamma2 的螺旋3上的半胱氨酸313位点与 PPARgamma 形成共价修饰。
Grouped product items
规格 价格 库存 数量
5mg
¥245.00
现货
10mg
¥315.00
现货
25mg
¥595.00
现货
50mg
¥1,015.00
现货
100mg
¥1,400.00
现货
200mg
¥1,820.00
现货
500mg
¥3,115.00
现货
10mM * 1mL in DMSO
¥315.00
现货
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重要通知:仅供研究使用。我们不向患者销售。

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生物活性
Discription T0070907 was identified as a potent and selective PPARgamma antagonist. With an apparent binding affinity (concentration at 50% inhibition of [(3)H]rosiglitazone binding or IC(50)) of 1 nm, T0070907 covalently modifies PPARgamma on cysteine 313 in helix 3 of human PPARgamma2.
Targets
Target Value
产品信息
目录号 A11588
分子式 C12H8ClN3O3
分子量 277.66
CAS号 313516-66-4
SMILES ClC1=CC=C([N+]([O-])=O)C=C1C(NC2=CC=NC=C2)=O
其他名称 T 0070907
储存条件

Store lyophilized at -20ºC, keep desiccated.
In lyophilized form, the chemical is stable for 36 months.
In solution, store at -20ºC and use within 3 months to prevent loss of potency. Aliquot to avoid multiple freeze/thaw cycles.

溶解性数据
In vitro (25°C) DMSO 24 mg/mL (86.43 mM)
Water Insoluble
Ethanol Insoluble
In vivo 5% DMSO+45% PEG 300+ddH2O 8 mg/mL
* <1 mg/ml means slightly soluble or insoluble.
* Please note that Adooq tests the solubility of all compounds in-house, and the actual solubility may differ slightly from published values. This is normal and is due to slight batch-to-batch variations.
Preparing Stock Solutions
Concentration / Solvent Volume / Mass 1 mg 5 mg 10 mg
0.1 mM 36.02 mL 180.08 mL 360.15 mL
0.5 mM 7.2 mL 36.02 mL 72.03 mL
1 mM 3.6 mL 18.01 mL 36.02 mL
5 mM 0.72 mL 3.6 mL 7.2 mL
Useful Calculator

This calculator helps you calculate mass of compound based on solution concentration, volume and molecular weight in a specific solution using the formula:

Mass (mg) = Concentration (mM) × Volume (mL) × Molecular Weight (g/mol)

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Please check COA/MSDS for correct molecular weight.

Calculate the dilution required to prepare a stock solution.
This equation is commonly abbreviated as: C1V1 = C2V2

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    C2

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